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Thread: Converting Between Kc and Kp
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09-26-08, 01:13 AM #3Re: Converting Between Kc and Kp
Errr...by Kc and Kp, are you by chance talking about specific heats? Define your nomenclature. Different disciplines have different meanings for the same symbols.
enf-Jesus its been like 12 minutes and you're already worried about stats?! :-P
Bigdog-Sweet home Alabama you are an idiot.
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09-30-08, 04:37 PM #6
Re: Converting Between Kc and Kp
Well, I'll just show you the calculations. I'd presume you've supposedly gone over it in class or something.
Given:
N2(g)+3H2(g) =2NH3(g)
Kc=9.60 at 300 C.
So, hopefully you know that PV=nRT...
Or, if you tinker with the equation a bit:
P=RT*(n/V)
...and n/V is the same thing as the concentration!
Continuing on:
Kc = ([NH3]2)/([N2][H2]3)
So, to convert the concentrations into partial pressures, each concentration must be multiplied by RT...
Kp = (([NH3]RT)2)/([N2]RT([H2]RT)3)
Simplifying that a bit, in this case you'll end up with...
Kp=Kc*((RT)2)/((RT)4)
Kp= Kc/(RT)2
Finally, plugging in the numbers, you'll end up with...
Kp= 9.60/(0.0821*573)2
Kp= 2.21x103
Of course, I could have lost some vital bit of the equation due to all of the obnoxious coding... :P
I showed you the general idea at the beginning anyway, P=RT*(n/V). Thus, you can freely convert between the concentration (n/V) and the pressure. The only thing to worry about is keeping the powers of RT straight.
EDIT: Erm, welcome to TTP. I suppose I missed this thread a couple of days ago...
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