Thread: Math question... Soysoldiers not allowed.

Because he probably knows the exact terminology for this one.


So I was posed this question earlier and it nearly made my brain explode. Which I think is it's sole purpose.


If you randomly choose an answer to this question, what's your percentage chance to get it correct?

A) 25%

B) 50%

C) 60%

D) 25%

Originally Posted by Kanati8869

Because he probably knows the exact terminology for this one.


So I was posed this question earlier and it nearly made my brain explode. Which I think is it's sole purpose.


If you randomly choose an answer to this question, what's your percentage chance to get it correct?

A) 25%

B) 50%

C) 60%

D) 25%

None of the above.

Maybe... maybe not. Show your work!!!

While you have 25% listed up there twice, thus making the "correct" answer B - 50%, thus making the correct answer 25% (again, listed twice) making the correct answer 50%... and so on... none of these are entirely true.

Because even in a "random" situation like this there is such thing as a random answer. If I am choosing, there are odds (not 25-25-25-25) for my choice of a correct answer based on my background and profile. You could average that out (say, for example, C is chosen by 40% of those polled) but this would still not give a strong enough result to assume correct percentages on any individual.

If other tools are used to generate a "random" answer, you would also have to explore what goes into influencing that result to determine the probability of that answer being correct as well.

So... oddly enough, I agree with the duck. None of those answers are correct. So... 0% chance.

Originally Posted by Kanati8869

Maybe... maybe not. Show your work!!!

God damn math teacher-esque people.

You have 25% listed twice, they're the exact same answer. By that, you have 3 options, (a, b, c) which means you have a 1:3 chance of getting the correct answer, or 33.3% (repeating symbol over the final 3).

Kanati, we will not do your homework for you.

Like quick said ...

Assuming that ONE of the answers is correct, one would have a 25% chance of selecting the correct answer. However, two of the answers listed, A and D, equal 25%. So "if" 25% were the "correct" answer that would mean that you would have a 2 in 4 chance (50% chance) of selecting 25% as the correct answer. This means that the answer would have to be 50%, which would mean that A & D cannot be the answer. However, if 50% is the answer then you have only a 1 in 4 chance (25% chance) of getting the "correct" answer. And the vicious cycle continues. C, 60% is there for the ride.

I think this is called a "pair of ducks."

Lol, TPG and math. When will we [s]learn[/s] unlearn why we don't do math here.

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What we need is for someone to come in to this thread and tirelessly argue why 60% is correct despite evidence.

The answer is 47...

Respectfully,
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